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Gaming > Chess analysis > Re: Has Checker...
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Re: Has Checkers Been Solved?

by torbenm@[EMAIL PROTECTED] (Torben =?iso-8859-1?Q?=C6gidius?= Mogense Mar 25, 2008 at 04:18 PM

samsloan <samhsloan@[EMAIL PROTECTED]
> writes:

> One factor to be considered is that the number of possible moves in a
> backgammon games is infinite. The players could easily just keeping
> hitting each other to infinity.

That doesn't matter, as long as the number of possible board positions
is finite (which it is).

The main difference between Backgammon and, say, Checkers is not the
possibility of infinite play but the fact that Backgammon involves
random elements, so few positions are definitely winning or definitely
losing -- all you can say is the probability of winning with perfect
play (i.e., always picking the move that gives you the best winning
probability after moving).

You can solve Backgammon by for each possible position have edges to
every other position that it is possible to get to in one move, and
label each edge with the dice outcome that allow this move).

This can be translated into a set of equations that you can solve to
find the probability of each possible position being winning or
losing.  The set of equations is huge, but finite.

	Torben




 1 Posts in Topic:
Re: Has Checkers Been Solved?
torbenm@[EMAIL PROTECTED]  2008-03-25 16:18:22 

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tan12V112 Tue May 13 15:52:46 CDT 2008.