On Mon, 28 Apr 2008 12:51:10 +0200, Henk Uijterwaal <henku@[EMAIL PROTECTED]
>
wrote:
>Lurfys Maw wrote:
>> We have a little social duplicate club with 6 couples that meets once
>> a month. We usually either draw for partners or let couples play as
>> partners and use a modified Howell movement for 3 tables.
>>
>> It has been suggested that it might be fun to mix it up a bit and play
>> boys against girls or some other team arrangement. If we had 4 or 8
>> pairs, I could do a team tournament, but I can't figure out a way to
>> play 6 against 6.
>
>The men are pairs A, B and C. The women pairs 1, 2 and 3.
>
>Table 1 2 3
> NS EW Brd NS EW Brd NS EW Brd
>Round 1 A 1 1-6 B 2 7-12 C 3 13-18
>Round 2 3 B 1-6 1 C 7-12 2 A 13-18
>
>On boards 1-6 A+B and 1+3 compare scores, 7-12 B+C and 1+2, 13-18
>A+C and 2+3. Add up the imps won/lost by A, B and C (and 1,2,3).
This is an interesting solution.
You've set up three team-of-four events where each event takes place
serially at the same table, rather than simultaneously at separate
tables, and the players, rather than the boards, move.
Each pair gets to compete with each of the other two pairs in their
3-pair team in a team-of-four event.
Each pair gets to sit at the same table as 2 of the 3 opposing pairs
and they compete directly (NS-NS or EW-EW) with the other pair.
It uses standard team-of-four scoring.
All in all, a nice solution.
Any comments on this vs the solution proposed by Ken or my solution
proposed in response to his?
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