by nickobento@[EMAIL PROTECTED]
Feb 5, 2008 at 07:25 PM
On Feb 4, 1:27 am, "markste...@[EMAIL PROTECTED]
" <markste...@[EMAIL PROTECTED]
>
wrote:
> Helix rules:
>
> Start with an initially empty hexagonally tessellated surface of a
> torus.
>
> Winning conditions for Black: Form a right handed helical loop or any
> closed loop surrounding the circular axis of the torus except for a
> left handed helical loop.
>
> Winning conditions for White: Form a left handed helical loop or any
> closed loop surrounding the linear axis of the torus except for a
> right handed helical loop.
In Helix, is there a problem with a "bagel cut" loop (i.e. a loop that
runs where the cut in a bagel would be)? It seems like you could have
two "bagel cut" loops, one in each color, and no winner. Is this
true, or is this ruled out in some way that I haven't seen?
N
