Miss Elaine Eos wrote:
> And again, sorry if I'm being unclear. I normally try to be pretty good
> about this stuff, but I guess I'm very tired this week, as I've caught
> myself asking a couple of questions that just turned out to be silly
> bugs on my part. I'll be more careful, going forward.
The vector solution for this, by the way, would be to write out the
vector equation of the plane:
{x: (x - p) dot n = 0},
where X is the point you're testing, P is a point on the plane (i.e.,
any of the points of the triangle), and n is the normal vector of the
plane (i.e., the cross product of any two sides of the triangle). Then
you write x as (x_x, x_y, x_z), and simply expand the equation and solve
for x_y.
--
Erik Max Francis && max@[EMAIL PROTECTED]
&& http://www.alcyone.com/max/
San Jose, CA, USA && 37 20 N 121 53 W && AIM, Y!M erikmaxfrancis
Chance favors the trained mind.
-- Louis Pasteur
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